AcWing 787. 归并排序
原题链接
简单
作者:
aventador
,
2020-03-04 13:43:40
,
所有人可见
,
阅读 722
C++ 代码
# include <iostream>
using namespace std;
const int N = 1e5 + 10;
int q[N], tmp[N], n;
void merge_sort(int q[], int l, int r)
{
// 递归出口
if(l >= r) return;
// 取中间值
int mid = l + r >> 1;
// 递归过程
merge_sort(q, l, mid), merge_sort(q, mid + 1, r);
// 归并过程
int k = 0, i = l, j = mid + 1;
while (i <= mid && j <= r)
if (q[i] <= q[j]) tmp[k ++] = q[i ++];
else tmp[k ++] = q[j ++];
while (i <= mid) tmp[k ++] = q[i ++];
while (j <= r) tmp[k ++] = q[j ++];
// 复制过程
for (i = l, j = 0; i <= r; i ++, j ++) q[i] = tmp[j];
}
int main()
{
scanf("%d", &n);
for (int i = 0; i < n; i ++) scanf("%d", &q[i]);
merge_sort(q, 0, n - 1);
for (int i = 0; i < n; i ++) printf("%d ", q[i]);
return 0;
}