使用单个unordered_map存储target值与第一个数组的差即可

#include <iostream>
#include <unordered_map>
using namespace std;

const int N = 1e5 + 10;
int n, m, x, t;

int main()
{
    cin >> n >> m >> x;
    unordered_map<int, int> record;

    for (int i = 0; i < n; ++i) {
        cin >> t;
        record[x - t] = i;
    }

    for (int j = 0; j < m; ++j)
    {
        cin >> t;
        if (record.count(t)) 
        {
            cout << record[t] << " " << j << endl;
            break;
        }
    }
    return 0;
}