知识点：模拟、字符串处理

我的做法

#include <iostream>
#include <cstring>
#include <algorithm>
using namespace std;
const int N = 15;
int n, id1, id2;
string name[N], s[N], e[N];
int main() {
    cin >> n;
    for (int i = 0; i < n; i ++ ) cin >> name[i] >> s[i] >> e[i];
    string s1 = s[0], s2 = e[0];
    for (int i = 0; i < n; i ++ ) {
        if(s[i] < s1) s1 = s[i], id1 = i;
        if(e[i] > s2) s2 = e[i], id2 = i;
    }
    cout << name[id1] << ' ' << name[id2] << endl;
    return 0;
}

看了y总的代码后进行的改进

#include <iostream>
#include <cstring>
#include <algorithm>
using namespace std;
const int N = 15;
int n, id1, id2;
string name, s, e, s1, s2, n1, n2;
int main() {
    cin >> n;
    for (int i = 0; i < n; i ++ ) {
        cin >> name >> s >> e;
        if(!i || s < s1) s1 = s, n1 = name;
        if(!i || e > s2) s2 = e, n2 = name;
    }
    cout << n1 << ' ' << n2 << endl;
    return 0;
}