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b站同名账号分享力扣杯历届真题视频题解，也欢迎大家提出宝贵意见！

思路：模拟

• 思路参见 3640. 删除字符串 题解，比较时比较所有 $8$ 种情况即可

代码（C++）

#include <bits/stdc++.h>
using namespace std;

int main() {
    string s;
        cin >> s;
        int n = s.size();

        string ret = "";

        for(int i = 0; i < n; i++) {
            string t = s.substr(i, 3);
            if(t == "gzu" || t == "Gzu" || t == "gZu" || t == "gzU" || t == "GZu" || t == "GzU" || t == "gZU" || t == "GZU") {
                i = i + 2;
            } else {
                ret += s[i];
            }
        }

        cout << ret;
    return 0;
}

时间复杂度：$O(n)$