AcWing 282. 石子合并
原题链接
简单
作者:
Java小码农
,
2021-07-21 16:04:49
,
所有人可见
,
阅读 134
C++ 代码
#include<iostream>
#include<algorithm>
using namespace std;
const int N = 310;
int n;
int s[N];
int f[N][N];
int main()
{
scanf("%d",&n);
for(int i = 1;i <= n;i ++ ) scanf("%d",&s[i]);
for(int i = 1;i <= n;i ++ ) s[i] += s[i - 1];
for(int len = 2;len <= n; len ++)
for(int i = 1;i + len - 1 <= n;i ++)
{
int l = i,r = i + len - 1;
f[1][1] = 1e8;
for(int k = l;k < r;k ++)
f[l][r] = min(f[l][r],f[l][k] + f[k + 1][r] + s[r] - s[i - 1]);
}
printf("%d\n",f[1][n]);
return 0;
}