#include <iostream>
using namespace std;

const int N=1010;

string name[N],code[N];

int main(){
    int n;
    int count=0;//修改密码的个数,初值为0
    cin>>n;
    for(int i=0;i<n;i++){
        string id,password;
        cin>>id>>password;
        string s=password;//用来暂存原来的密码，用于最后的判断输出
        int len=password.length();
        for(int j=0;j<len;j++){//根据题目条件判断是否需要修改密码
            if(password[j]=='1'){
                password[j]='@';
            }
            if(password[j]=='0'){
                password[j]='%';
            }
            if(password[j]=='l'){
                password[j]='L';
            }
            if(password[j]=='O'){
                password[j]='o';
            }
        }
        if(s!=password){//当前密码被修改过,更新count值并将账户和密码存入数组
            name[count]=id;
            code[count]=password;
            count++;
        }
    }
    if(count==0){//没有要修改的密码
        if(n==1){
            printf("There is 1 account and no account is modified");
        }
        else{
            printf("There are %d accounts and no account is modified",n);
        }
    }
    else{
       cout<<count<<endl;
       for(int i=0;i<count;i++){
           cout<<name[i]<<" "<<code[i]<<endl;
       }
    }
    return 0;
}