AcWing 792. 高精度减法
原题链接
简单
作者:
今天Code了吗
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2021-03-28 14:32:00
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所有人可见
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阅读 276
#include <iostream>
#include <vector>
using namespace std;
//判断是否A≥B
bool cmp(vector<int> &A, vector<int> &B){
if(A.size() != B.size()) return A.size() > B.size();
for(int i = A.size() - 1; i >= 0; i--){
if(A[i] != B[i]){
return A[i] > B[i];
}
}
return true;
}
vector<int> sub(vector<int> &A, vector<int> &B){
vector<int> C;//C = A - B
for(int i = 0, t = 0; i < A.size(); i++){
t = A[i] - t;
if(i < B.size()) t -= B[i];
C.push_back((t + 10) % 10);
if(t < 0) t = 1;
else t = 0;
}
//解决前导0
while (C.size() > 1 && C.back() == 0) C.pop_back();
return C;
}
int main(){
string a, b;
vector<int> A, B;
// C = A + B, A >= 0, B >= 0
cin >> a >> b;
for(int i = a.size() - 1; i >= 0; i--){
A.push_back(a[i] - '0');
}
for(int i = b.size() - 1; i >= 0; i--){
B.push_back(b[i] - '0');
}
if(cmp(A, B)){
auto C = sub(A, B);
for(int i = C.size() - 1; i >= 0; i--) cout << C[i];
} else{
auto C = sub(B, A);
cout << "-";
for(int i = C.size() - 1; i >= 0; i--) cout << C[i];
}
return 0;
}