AcWing 788. 逆序对的数量
原题链接
简单
作者:
今天Code了吗
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2021-03-27 13:29:00
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所有人可见
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阅读 266
#include <iostream>
using namespace std;
const int N = 100010;
int q[N], temp[N];
typedef long long LL;
LL merge_sort(int l, int r){
if(l >= r) return 0;
int mid = l + r >> 1;
LL result = merge_sort(l, mid) + merge_sort(mid + 1, r);
int k = 0, i = l, j = mid + 1;
while (i <= mid && j <= r){
if(q[i] <= q[j]) temp[k++] = q[i++];
else{
temp[k++] = q[j++];
result += mid - i + 1;
}
}
while (i <= mid) temp[k++] = q[i++];
while (j <= r) temp[k++] = q[j++];
for(int i = l, j = 0; i <= r; i++, j++) q[i] = temp[j];
return result;
}
int main() {
int n;
scanf("%d", &n);
for(int i = 0; i < n; i++) scanf("%d", &q[i]);
cout << merge_sort(0, n - 1) << endl;
return 0;
}