题目描述
blablabla
样例
blablabla
算法1
list + 递归
时间复杂度
Time complexity:
Constructor: O(N + L)
next(): O(1)
hasNext(): O(1)
Space complexity : O(N + D)
参考文献
Java 代码
/**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* public interface NestedInteger {
*
* // @return true if this NestedInteger holds a single integer, rather than a nested list.
* public boolean isInteger();
*
* // @return the single integer that this NestedInteger holds, if it holds a single integer
* // Return null if this NestedInteger holds a nested list
* public Integer getInteger();
*
* // @return the nested list that this NestedInteger holds, if it holds a nested list
* // Return empty list if this NestedInteger holds a single integer
* public List<NestedInteger> getList();
* }
*/
public class NestedIterator implements Iterator<Integer> {
private List<Integer> list = new ArrayList<Integer>();
private int position = 0; // Pointer to next integer to return.
public NestedIterator(List<NestedInteger> nestedList) {
flattenList(nestedList);
}
private void flattenList(List<NestedInteger> nestedList) {
for (NestedInteger nestedInteger : nestedList) {
if (nestedInteger.isInteger()) {
list.add(nestedInteger.getInteger());
} else {
flattenList(nestedInteger.getList());
}
}
}
@Override
public Integer next() {
if (hasNext()){
return list.get(position++);
}
return null;
}
@Override
public boolean hasNext() {
return position < list.size();
}
}
/**
* Your NestedIterator object will be instantiated and called as such:
* NestedIterator i = new NestedIterator(nestedList);
* while (i.hasNext()) v[f()] = i.next();
*/