意外的简单
C++ 代码
#include<iostream>
using namespace std;
const int N = 300;
int b[N], p[N];
int main() {
int n, m;
cin >> n >> m;
for (int i = 1; i <= n; i++) {
cin >> p[i];
b[p[i]]++;
}
for (int i = 1; i <= n; i++) {
if (b[p[i]] > 1)cout << b[p[i]] - 1 << endl;
else cout << "BeiJu" << endl;
}
return 0;
}