#include<iostream>
using namespace std;

int a[100][100];

int main(){
    int n;
    while(cin >> n, n){
        for(int i = 0; i < n; ++i){
            a[i][i] = 1;
            for(int j = i + 1, k = 2; j < n; ++j, ++k) 
                a[i][j] = k;
            for(int j = i + 1, k = 2; j < n; ++j, ++k)
                a[j][i] = k;
        }

        for(int i = 0; i < n; ++i){
            for(int j = 0; j < n; ++j)
                cout << a[i][j] << " ";
            cout << endl;
        }
        cout << endl;
    }

    return 0;
}

还有一种规律
abs( i - j ) + 1