不需要判断两个时间的大小，直接（b-a+24)%24

C++ 代码

#include <cstdio> 
#include <cmath>
#include <iostream>

using namespace std;

int main()
{
    int a, b;
    cin >> a >> b;

    if(a == b) printf("O JOGO DUROU 24 HORA(S)");
    else printf("O JOGO DUROU %d HORA(S)",(b-a+24)%24);

    return 0;
}