和上面一题一样，不过是改成整数，然后分两种情况输出

C++ 代码

#include <cstdio> 
#include <cmath>
#include <iostream>

using namespace std;

int main()
{
    double n;
    scanf("%lf",&n);

    int x = (int)(n*100);

    int m[12] = {10000, 5000, 2000, 1000, 500, 200, 100, 50, 25, 10, 5, 1};

    for(int i = 0; i < 12; i++){
        if(!i) printf("NOTAS:");
        if(i == 6) printf("\nMODEAS:");
        if(i < 6) printf("\n%d nota(s) de R$ %d.00",x/m[i], m[i]/100);
        else printf("\n%d moeda(s) de R$ %.2f",x/m[i], (double)m[i]/100);
        x %= m[i];
    }


    return 0;
}