全部转换成秒 可以少很多很多次判断

#include <iostream>
using namespace std;
int main()
{
    int a, b, c, d;
    cin >> a >> b >> c >> d;
    int start = a * 60 + b;
    int end = c * 60 + d;
    int spend_time = end - start;
    if (spend_time <= 0) spend_time += 1440;
    printf("O JOGO DUROU %d HORA(S) E %d MINUTO(S)",spend_time / 60, spend_time % 60); 
    return 0;
}