题目描述
blablabla
样例
blablabla
算法1
(暴力枚举) $O(n^2)$
blablabla
时间复杂度
参考文献
C++ 代码
blablabla
算法2
(暴力枚举) $O(n^2)$
blablabla
时间复杂度
参考文献
C++ 代码
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1000 + 10;
int a[maxn][maxn], b[maxn][maxn];
int n, m, k;
void insert(int x1, int y1, int x2, int y2, int c)
{
b[x1][y1] += c;
b[x2 + 1][y1] -= c;
b[x1][y2 + 1] -= c;
b[x2 + 1][y2 + 1] += c;
}
int main()
{
cin >> n >> m >> k;
for (int i = 1; i <= n; i++)
for (int j = 1; j <= m; j++)
scanf("%d", &a[i][j]);
for (int i = 1; i <= n; i++)
for (int j = 1; j <= m; j++)
insert(i, j, i, j, a[i][j]);
while (k--)
{
int x1, y1, x2, y2, c;
scanf("%d%d%d%d%d", &x1, &y1, &x2, &y2, &c);
insert(x1, y1, x2, y2, c);
}
for (int i = 1; i <= n; i++)
for (int j = 1; j <= m; j++)
b[i][j] += b[i - 1][j] + b[i][j - 1] - b[i - 1][j - 1];
for (int i = 1; i <= n; i++)
{
for (int j = 1; j <= m; j++)
printf("%d ", a[i][j]);
cout << endl;
}
}