#include <iostream>
using namespace std;
const int N = 110;
int a[N];
int n, total, cnt;
int main()
{
cin >> n;
for (int i = 0; i < n; i ++ ) cin >> a[i], total += a[i];
int avg = total / n; //因为必有解,先求出平均值
for (int i = 0; i < n - 1; i ++ )
{
if (a[i] != avg)
{
a[i + 1] += a[i] - avg; //逐个遍历,不满足平均值的就向下一个给出或拿入
cnt ++ ;
}
}
cout << cnt << endl;
return 0;
}