暴力枚举，跟c差不多，但要注意不要只考虑个位数加减

fn=[6,2,5,5,4,5,6,3,7,6]

x=int(input())-4
res=0

def count(num):
    if num==0:
        return fn[0]
    count=0
    while num>0:
        count+=fn[num%10]
        num//=10
    return count

for a in range(1000):
    for b in range(1000):
        c=a+b
        t=count(a)+count(b)+count(c)
        if t==x:
            res+=1

print(res)