非常easy的一道题

#include <iostream>
using namespace std;

string s1, s2;

int main()
{
    int ans = 0;

    cin >> s1 >> s2;

    for (int i = 0; i < s1.size(); i ++ )
    {
        if (s1[i] != s2[i])
        {
            ans ++;
            if (s1[i] == '*') s1[i] = 'o';
            else s1[i] = '*';
            if (s2[i+1] == '*') s2[i+1] = 'o';
            else s2[i+1] = '*';
        }
    }


    printf("%d", ans);
    return 0;
}