题目描述

逻辑简单，就是格式有点麻烦

样例

#include<iostream>
using namespace std;
#include<cstdio>
int main(){
    int n;
    scanf("%d",&n);
    int x=0,y=0,z=0;
    for(int i=1;i<=n;i++){
        int a;
        char t;
        cin>>a>>t;
        if(t=='C') x=x+a;
        else if(t=='R') y=y+a;
        else z=z+a;
    }
    int s=x+y+z;
    printf("Total: %d animals\n",s);
    printf("Total coneys: %d\n",x);
    printf("Total rats: %d\n",y);
    printf("Total frogs: %d\n",z);
    printf("Percentage of coneys: %.2lf \%\n",(double)x/s*100);
    printf("Percentage of rats: %.2lf \%\n",(double)y/s*100);
    printf("Percentage of frogs: %.2lf \%\n",(double)z/s*100);
    return 0;


}

算法1

(暴力枚举) $O(n^2)$

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时间复杂度

参考文献

C++ 代码

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算法2

(暴力枚举) $O(n^2)$

blablabla

时间复杂度

参考文献

C++ 代码

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