题目描述

实验 较麻烦

样例

#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
    int n,a=0,c=0,r=0,f=0,t,s=0,i;
    cin>>n;

    for ( i=1;i<=n;i++)//循环加判断
    {
        char q;
        cin>>a>>q;
        t=a;
        if(q=='C') c+=a;
        if(q=='R') r+=a;
        if(q=='F') f+=a;
        s+=t;
    }
        double s1=0,s2=0,s3=0;//注意变量精度
    s1=(double)c/(double)s*100;
    s2=(double)r/(double)s*100;
    s3=(double)f/(double)s*100;
    printf("Total: %d animals\nTotal coneys: %d\nTotal rats: %d\nTotal frogs: %d\n",s,c,r,f);
    printf("Percentage of coneys: %.2lf %\nPercentage of rats: %.2lf %\nPercentage of frogs: %.2lf %",s1,s2,s3);//注意换行
    return 0;
}

算法1

(暴力枚举) $O(n^2)$

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时间复杂度

参考文献

C++ 代码

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算法2

(暴力枚举) $O(n^2)$

blablabla

时间复杂度

参考文献

C++ 代码

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