题目描述

实验

样例

#include <iostream>
using namespace std;
int main()
{
    int a, n;
    char c;
    scanf("%d", &n);
    int sum = 0, C = 0, R = 0, F = 0; 
    while (n -- ) 
    {
        cin>>a>>c;
        if(c=='C') C+=a; 
        if(c=='R') R+=a;
        else if(c=='F') F+=a;
        sum+=a;
    }
    double c2=(1.0*C/sum)*100;
    double r=(1.0*R/sum)*100;
    double f=(1.0*F/sum)*100;
    printf("Total: %d animals\n", sum);
    printf("Total coneys: %d\n", C);
    printf("Total rats: %d\n", R);
    printf("Total frogs: %d\n", F);
    printf("Percentage of coneys: %.2lf %%\n", c2);
    printf("Percentage of rats: %.2lf %%\n", r);
    printf("Percentage of frogs: %.2lf %%\n", f); 

    return 0;
}
----------

### 算法1
##### (暴力枚举)  $O(n^2)$

blablabla

#### 时间复杂度

#### 参考文献

#### C++ 代码

blablabla

----------

### 算法2
##### (暴力枚举)  $O(n^2)$

blablabla

#### 时间复杂度

#### 参考文献


#### C++ 代码

blablabla
```