本题用C++写要用高精度，py直接模拟即可

py中的字符串反转可以用切片操作，对于字符串s，将它反转：s = s[::-1]

A = input()
B = A[::-1]

cnt = 0
success = True
while A != B:
    if cnt == 10:
        success = False
        break
    C = int(A) + int(B)
    print(f"{A} + {B} = {C}")
    A = str(C)
    B = A[::-1]
    cnt += 1

if success:
    print(f"{A} is a palindromic number.")
else:
    print("Not found in 10 iterations.")