本题用C++写要用高精度，py直接模拟即可

py中的字符串反转可以用切片操作，对于字符串s，将它反转：s = s[::-1]

n,k = input().split()
k = int(k)

cnt = 0
reverse = n[::-1]
while reverse != n:
    cnt += 1
    Sum = int(n) + int(reverse)
    n = str(Sum)
    reverse = n[::-1]
    if cnt == k:
        break

print(n)
if cnt == k:
    print(k)
else:
    print(cnt)