题目描述

1.注意0和O的区别
2.情况要讨论清楚
3。分钟大于60记得进一

样例

#include<bits/stdc++.h>
using namespace std;
int main(){
    int a,b,c,d;
    int x,y;
    cin>>a>>b>>c>>d;
    if(a<c){
        x=(c*60+d-(a*60+b))/60;
        y=(c*60+d-(a*60+b))%60;
        cout<<"O JOGO "<<"DUROU "<<x<<" HORA(S) E "<<y<<" MINUTO(S)"<<endl;
    }else if(a==c&&b==d){
        printf("O JOGO DUROU 24 HORA(S) E 0 MINUTO(S)\n");
    }else if(a==c&&b<d){
        printf("O JOGO DUROU 0 HORA(S) E %d MINUTO(S)\n",d-b);
    }
    else{
        x=(23-a+c);
        y=d+60-b;
        if(y>60){
            x=x+1;
            y=y-60;
        }
        cout<<"O JOGO "<<"DUROU "<<x<<" HORA(S) E "<<y<<" MINUTO(S)"<<endl;
    }
    return 0;
}

算法1

(暴力枚举) $O(n^2)$

blablabla

时间复杂度

参考文献

C++ 代码

blablabla

算法2

(暴力枚举) $O(n^2)$

blablabla

时间复杂度

参考文献

C++ 代码

blablabla