题目描述

dongwu就是判断麻烦

样例

#include <iostream>
using namespace std;
int main()
{
    string a, b, c;

    cin >> a >> b >> c;

    if (a == "vertebrado")//一层一层的判断
    {
        if (b == "ave")
        {
            if (c == "carnivoro") cout << "aguia" << endl;
            else if(c == "onivoro") cout << "pomba" << endl;
        }

        if (b == "mamifero")
        {
            if (c == "onivoro") cout << "homem" << endl;
            else if (c == "herbivoro") cout << "vaca" <<endl;
        }
    }
    if (a == "invertebrado")
    {
        if (b == "inseto")
        {
            if (c == "hematofago") cout << "pulga" << endl;
            else if (c == "herbivoro") cout <<"lagarta" << endl;
        }
        if (b == "anelideo")
        {
            if (c == "hematofago") cout << "sanguessuga" << endl;
            else if (c == "onivoro") cout << "minhoca" << endl;
        }
    }
    return 0;

}

算法1

(暴力枚举) $O(n^2)$

blablabla

时间复杂度

参考文献

C++ 代码

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算法2

(暴力枚举) $O(n^2)$

blablabla

时间复杂度

参考文献

C++ 代码

blablabla