13.//Floyd判断最短路(多源)
#include<cstring>
#include<iostream>
#include<algorithm>
using namespace std;
const int N = 210, INF = 1e9;
int n, m, Q;
int d[N][N];
void floyd() {
for(int k = 1; k <= n; k ++)
for(int i = 1; i <= n; i ++)
for(int j = 1; j <= n; j ++)
d[i][j] = min(d[i][j], d[i][k] + d[k][j]);
}
int main() {
cin >> n >> m >> Q;
for(int i = 1; i <= n; i ++)
for(int j = 1; j <= n; j ++)
if(i == j) d[i][j] = 0;
else d[i][j] = INF;
while(m --) {
int a, b, w;
cin >> a >> b >> w;
d[a][b] = min(d[a][b], w);
}
floyd();
while(Q --) {
int a, b;
cin >> a >> b;
if(d[a][b] > INF / 2) puts("impossible");
else printf("%d\n", d[a][b]);
}
return 0;
}