floyd-时刻记住kij
#include<iostream>
using namespace std;
const int N = 210, INF = 1e9;
int n, m, k, x, y, z;
int d[N][N];
void floyd() {
for (int k = 1; k <= n; k ++ ) {
for (int i = 1; i <= n; i ++ ) {
for (int j = 1; j <= n; j ++ ) d[i][j] = min(d[i][j], d[i][k] + d[k][j]);
}
}
}
int main() {
cin >> n >> m >> k;
for (int i = 1; i <= n; i ++ ) {
for (int j = 1; j <= n; j ++ ) {
if (i == j) d[i][j] = 0;
else d[i][j] = INF;
}
}
while (m -- ) {
cin >> x >> y >> z;
d[x][y] = min(d[x][y], z);
}
floyd();
while (k -- ) {
cin >> x >> y;
if (d[x][y] > INF / 2) puts("impossible");
else cout << d[x][y] << endl;
}
return 0;
}