输入
3
56 67 65
78 45 67
56 55 57
58

输出
yes 292

#include<iostream>
using namespace std;

const int N=100;

int main(){
    int n,b,a[N][N];
    cin>>n;
    for(int i=0;i<n;i++){
        for(int j=0;j<n;j++){
            cin>>a[i][j];
        }
    }
    cin>>b;

    int sum=0;
    int i=0,j=0;
    while(i<n && j<n){
        sum+=a[i][j];
        if(b>=a[i][j])j++;
        else i++;
    }
    if(j==n)cout<<"yes "<<sum<<endl;
    else cout<<"no"<<endl;
    return 0;
}