1. AcWing 763. 循环相克令( https://www.acwing.com/problem/content/765/ )

#include<iostream>
#include<cstring>
using namespace std;
int main()
{
    int t;
    string ch1,ch2;
    cin>>t;
    while(t--){
        cin>>ch1>>ch2;
        if(ch1==ch2) cout<<"Tie"<<endl;
        else{
            if(ch1=="Hunter")
                if(ch2=="Bear") cout<<"Player2"<<endl;
                else cout<<"Player1"<<endl;
            if(ch1=="Bear")
                if(ch2=="Hunter") cout<<"Player1"<<endl;
                else cout<<"Player2"<<endl;
            if(ch1=="Gun")
                if(ch2=="Hunter") cout<<"Player2"<<endl;
                else cout<<"Player1"<<endl;
        }
    }

    return 0;
}

#include<iostream>
#include<cstring>
using namespace std;
int get(string s)
{
    if(s=="Hunter") return 0;
    if(s=="Bear") return 1;
    return 2;
}
int main()
{
    int t;
    string a,b;
    cin>>t;
    while(t--)
    {
        cin>>a>>b;
        int x=get(a),y=get(b);
        if(x==y) cout<<"Tie"<<endl;
        else if((x+1)%3==y) cout<<"Player2"<<endl;
        else cout<<"Player1"<<endl;
    }
    return 0;
}

啥也不说了，y总牛逼!!!

2. AcWing 756. 蛇形矩阵( https://www.acwing.com/problem/content/758/ )

3.

4. AcWing 764. 输出字符串( https://www.acwing.com/problem/content/766/ )

#include<iostream>
#include<string>
using namespace std;
int main()
{
    string a,b;
    getline(cin,a);
    for(int i=0;i<a.size()-1;i++)
        b+=a[i]+a[i+1];

    b+=a[a.size()-1]+a[0];
    cout<<b;
    return 0;
}

#include<iostream>
#include<string>
using namespace std;
int main()
{
    string a,b;
    getline(cin,a);
    int len=a.size();
    for(int i=0;i<len;i++)
        b+=a[i]+a[(i+1)%len];//b+=(char)(a[i]+a[(i+1)%len]);

    cout<<b;
    return 0;
}

5.AcWing 767. 信息加密( https://www.acwing.com/problem/content/description/769/ )

这个题思路不难，但就是看怎么做最快了

#include<iostream>
#include<cstring>
using namespace std;
int main()
{
    string str;
    getline(cin,str);
    for(int i=0;str[i];++i){
        if(str[i]<='y'&&str[i]>='a'||str[i]>='A'&&str[i]<='Y')
            str[i]++;
        else if(str[i]=='z') str[i]='a';
        else if(str[i]=='Z') str[i]='A';
    }
    cout<<str;
}

y总

#include<iostream>
#include<cstring>
using namespace std;
int main()
{
    string s;
    getline(cin,s);

    for(int i=0;s[i];++i)
        if(s[i]<='z'&&s[i]>='a') s[i]=(s[i]-'a'+1)%26+'a';
        else if(s[i]<='Z'&&s[i]>='A') s[i]=(s[i]-'A'+1)%26+'A';

    cout<<s;
    return 0;
}