纯模拟

#include<iostream>

using namespace std;

int month[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
int k=0,d=6;
int main()
{
    for(int i=2000;i<=2020;i++)
    {
        if(i%4==0&&i%100!=0||i%400==0)
         month[2] = 29;
        for(int j=1;j<=12;j++)
        {
            for(int l=1;l<=month[j];l++)
            {
                if(d==1||l==1)
                k+=2;else
                 k++;

                if(d==7) d=1;
                else d++;

                if(i==2020&&j==10&&l==1)
                 {
                    printf("%d\n",k);
                    return 0;
                 }
            }
        }
        if(month[2]==29)
        month[2]=28;
    }


    return 0;
 } 
 ```

 ![星期几？.jpg](https://cdn.acwing.com/media/article/image/2023/04/03/262151_7fb7d497d2-星期几？.jpg) 
 ### 模拟
 ```
 #include <iostream>
#include <cstring>
#include <algorithm>

using namespace std;
string monthh[12]={"January","February","March","April","May","June","July","August","September","October","November","December"};
string dayy[7]={"Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","Sunday"};
int monthday[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
int day,year;
string month;
int main()
{
    while(cin>>day>>month>>year){
        int s=0,c=0,n=0;
        for(int i=1;i<year;i++)
        {
            if(i%4==0&&i%100!=0||i%400==0)
            s+=366;
            else s+=365;
        }

        if(year%4==0 && year%100!=0 || year%400==0)
         monthday[2] = 29;
         else monthday[2] = 28;

        for(int i=1;i<=12;i++)
        {
            if(monthh[i]==month)
            {
                n=i; break;
            }
        }

        for(int i=1;i<=n;i++)
        {
            c+=monthday[i];
        }

        c+=day;
        c--;

        cout<<dayy[(s+c)%7]<<endl;
    }
    return 0;
}

对于很多模拟问题，如果是需要控时，可以整体求，再单次求。

字符型数字 转化成整型 a[i] -‘0’即可.