658. 一元二次方程公式

include[HTML_REMOVED]

include[HTML_REMOVED]

int main()
{
double a,b,c;
double x1, x2;
scanf(“%lf %lf %lf”, &a,&b,&c);
if (b * b - 4 * a * c < 0)
{
printf(“Impossivel calcular”);
}
else if (a == 0)
{
printf(“Impossivel calcular”);
}
else
{
x1 =(-b + sqrt(b * b - 4 * a * c)) / (2a);
x2 = (-b - sqrt(b * b - 4 * a * c)) / (2a);
printf(“R1 = %.5lf\n”,x1);
printf(“R2 = %.5lf”, x2);
}
return 0;
}