#include<bits/stdc++.h>
using namespace std;
#define IOS ios::sync_with_stdio(0),cin.tie(0),cout.tie(0);
#define int long long
#define inf 0x3f3f3f3f
#define mod1 1000000007
#define mod2 998244353
#define f first
#define s second
#define pb push_back
#define eb emplace_back
#define fo(i,a,b) for(int i=a;i<=b;i++)
#define rep(i,a,b) for(int i=a;i>=b;i--)
#define m1(a,b) memset(a,b,sizeof a)
#define m2(a,b) memcpy(a,b,sizeof b)
using ld = long double;
using str = string;
using pi = pair<int,int>;
using pd = pair<ld,ld>;
using vi = vector<int>;
using vb = vector<bool>;
using vd = vector<ld>;
using vs = vector<str>;
using vpi = vector<pi>;
using vpd = vector<pd>;
const ld PI = acos((ld)-1);
const int dx[4]={1,0,-1,0},dy[4]={0,1,0,-1};
template<class T> using pqg = priority_queue<T,vector<T>,greater<T>>;
template<typename T, typename U> void umin(T& a, U b){if (a > b) a = b;}
template<typename T, typename U> void umax(T& a, U b){if (a < b) a = b;}
namespace IO{
inline int read()
{
int X=0; bool flag=1; char ch=getchar();
while(ch<'0'||ch>'9') {if(ch=='-') flag=0; ch=getchar();}
while(ch>='0'&&ch<='9') {X=(X<<1)+(X<<3)+ch-'0'; ch=getchar();}
if(flag) return X;
return ~(X-1);
}
inline void write(int X)
{
if(X<0) {X=~(X-1); putchar('-');}
if(X>9) write(X/10);
putchar(X%10+'0');
}
}
namespace math{
int qmi(int a,int k,int p)
{
int res=1%p;
while(k)
{
if(k&1) res=res*a%p;
a=a*a%p;
k>>=1;
}
return res;
}
bool is_prime(int x)
{
if (x < 2) return false;
for (int i = 2; i <= x / i; i ++ )
if (x % i == 0)
return false;
return true;
}
int gcd(int a,int b)
{
return b?gcd(b,a%b):a;
}
int exgcd(int a,int b,int &x,int &y)
{
if(!b)
{
x=1;y=0;
return a;
}
int d=exgcd(b,a%b,y,x);
y-=(a/b)*x;
return d;
}
vector<int> add(vector<int> &A, vector<int> &B) // C = A + B, A >= 0, B >= 0
{
if (A.size() < B.size()) return add(B, A);
vector<int> C;
int t = 0;
for (int i = 0; i < A.size(); i ++ )
{
t += A[i];
if (i < B.size()) t += B[i];
C.push_back(t % 10);
t /= 10;
}
if (t) C.push_back(t);
return C;
}
vector<int> sub(vector<int> &A, vector<int> &B) // C = A - B, 满足A >= B, A >= 0, B >= 0
{
vector<int> C;
for (int i = 0, t = 0; i < A.size(); i ++ )
{
t = A[i] - t;
if (i < B.size()) t -= B[i];
C.push_back((t + 10) % 10);
if (t < 0) t = 1;
else t = 0;
}
while (C.size() > 1 && C.back() == 0) C.pop_back();
return C;
}
vector<int> mul(vector<int> &A, int b) // C = A * b, A >= 0, b >= 0
{
vector<int> C;
int t = 0;
for (int i = 0; i < A.size() || t; i ++ )
{
if (i < A.size()) t += A[i] * b;
C.push_back(t % 10);
t /= 10;
}
while (C.size() > 1 && C.back() == 0) C.pop_back();
return C;
}
vector<int> div(vector<int> &A, int b, int &r) // A / b = C ... r, A >= 0, b > 0
{
vector<int> C;
r = 0;
for (int i = A.size() - 1; i >= 0; i -- )
{
r = r * 10 + A[i];
C.push_back(r / b);
r %= b;
}
reverse(C.begin(), C.end());
while (C.size() > 1 && C.back() == 0) C.pop_back();
return C;
}
}
namespace tu{
int h[100010],w[100010],e[100010],ne[100010],idx;
void add(int a,int b)
{
e[idx]=b,ne[idx]=h[a],h[a]=idx++;
}
void add(int a,int b,int c)
{
e[idx]=b,w[idx]=c,ne[idx]=h[a],h[a]=idx++;
}
}
using namespace IO;
using namespace math;
using namespace tu;
signed main(){
return 0;
}
159行。
无效的,无用的
正确的,中肯的,一针见血的
谢谢!