10进制转化为p进制的板子

string change(int n)
{
    string ans="";
    if (n==0) return "0";
    while (n)
    {
        int x= n%16;
        char c;
        if (x<10) c=x+'0';
        else c=x+'A'-10;
        ans=c+ans;
        n/=p;
    }
    return ans;
}

乘法表

#include <iostream>
#include <cstdio>
using namespace std;
int p;
string change(int n)  //10进制转化为p进制
{
    string ans="";
    while (n)
    {
        int t=n%p;
        if (t<10) ans=char(t+'0')+ans;
        else ans=char(t+'A'-10)+ans;

        n/=p;
    }
    return ans;
}
int main()
{
    cin>>p;
    for (int i=1;i<p;i++)
    {
        for (int j=1;j<=i;j++)
        {
            cout<<change(i)<<"*"<<change(j)<<"="<<change(i*j)<<" ";
        }
        cout<<endl;
    }
    return 0;
}